Three concurrent forces of the same magnitude | vedclass

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Question

(A) When $N$ forces of equal magnitude act on a single point and their resultant is zero,the angle $	heta$ between any two forces is given by:$	heta

Vedclass · Accepted Answer

$120^\circ$,equilateral triangle

Vedclass · Answer

(A) When $N$ forces of equal magnitude act on a single point and their resultant is zero,the angle $	heta$ between any two forces is given by:$	heta = \frac{360^\circ}{N} = \frac{360^\circ}{3} = 120^\circ$If these three vectors are represented by the three sides of a triangle placed head-to-tail,they form a closed loop. Since the magnitudes are equal and the angles between the vectors are $120^\circ$,the internal angles of the triangle formed by these vectors will be $60^\circ$ each,resulting in an equilateral triangle.

Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also,name the triangle formed by the forces as sides.

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